x+2/x^2=x-20

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Solution for x+2/x^2=x-20 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

x+2/(x^2) = x-20 // - x-20

x-x+2/(x^2)+20 = 0

2*x^-2 = -20 // : 2

x^-2 = -10

-2 < 0

1/(x^2) = -10 // * x^2

1 = -10*x^2 // : -10

-1/10 = x^2

x belongs to the empty set

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